[Question]:
Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis form a container, such that the container contains the most water.
Note: You may not slant the container.
[Analysis]:
Area(i,j) = Min(Ai, Aj) * (j-i);
The min of (Ai, Aj) decides the area of the container. For k, i<k<j, Area (i, k) < Area(i, j) if Ai < Aj: i.e. all Area(i,k) can be ruled out.
[Solution]:
public class Solution {int maxArea(vector<int>& height) {
int i=0, j=height.size()-1;
int ret=0;
while (i<j) {
ret = max(ret, min(height[i],height[j]) * (j-i));
if (height[i]<height[j]) i++;
else j--;
}
return ret;
}
}
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