Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given
return
Given
1->2->3->4->5->NULL
and k = 2
,return
4->5->1->2->3->NULL
.[Analysis]
Just need to be careful that the k could be larger than the length of the linked list.
[Solution]
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
if (head==null) return null;
ListNode p = head;
int count=0;
while (p.next!=null) {
count++;
p=p.next;
}
count++;
p.next = head;
n = n % count;
p=head;
while (n+1<count) {
n++;
p=p.next;
}
head = p.next;
p.next = null;
return head;
}
}
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